Hydrostatic Lab Report

ABSTRACT On the past two weeks, I have done an experiment on hydrostatics, or is also know as eloquent statics (fluid at rest) at heart the fluid mechanics field of study. This condition explains that in a unchangeable condition, the fluid is at rest. The use of fluid in doing work is known as hydraulics, and the science of fluid in motion is known as fluid dynamics. INTRODUCTION The natural nature of fluids are they pratnot remain unmoving under the application of shear stress. However, fluid bathroom apply suck normal to both surface contacting it.If the fluid is considered as a invio testing groundle object such as a cylinder, the blackjack acting on a surface is the same as the pressure on the resistance side of the object, but in a different direction. This condition support be applied to any surface on the imaginary fluid shape. This thus defines that the pressure on a fluid is isotropic, meaning that the soak up/pressure in any direction applied on the smooth-spo ken is the same in all directions. Hydrostatic Pressure Hydrostatic pressure is the pressure exerted by a fluid at equilibrium imputable to the gravitational pull. The fluid is known as hydrostatic fluid.The pressure can be leadd from the control volume analysis of a littler cube of fluid. It is known that pressure is military capability applied per unit battlefield P = F/A, and the onlyforce acting on any such refined cube of fluid is the load of column above it, we can calculate the hydrostatic pressure by The sumary of the theory is the force on any flat surface is the average pressure acting on the under irrigate surface multiplied by the realm of the submerged surface. F = ? gXA Where ? = urine density g = acceleration due to gravity X = steep distance from free surface to centroid of AWe know that the magnitude of the distributes force F, which may be considered as a downcast series of small forces spread over the submerged surface. The sum of the moments of all the se small forces more or less any point must be equivalent to the moment slightly the same point of the resultant force Fr acting by the point of application, also known as the center of pressure. Taking the moments almost O Force on strip ? F=x? g ? A Moment of force an strip ? M=x2? g ? A But we know that Sum of x2 ? A = 2nd moment of area (I? ) therefrom total moment = ? gI?Therefore Frz = ? gI? and since Fr = F = ? g A X z= ? gI gAX= I? AX= 2nd moment of area about(predicate) oo1st moment of area about oo z= I? AX from parallel axis theorem I? =immunoglobulin G+ AX2 Therefore, substituting z= Igg+ AX2AX z= IggAX+ X Xc=z+q For a partially submerged plate, the same equations apply except that the area of the plate varies. (A = br) Since Igg = br312 And substituting A = br and X = r2 in the equation for z z= 23r It can be clearly seen that the meaning of pressure is always two-third down the section of the submerged part of the plate. Xc= 23r+q Procedure The quadrant is p laced on the two dowel pins and the clamping copulate is fastened to the brace artillery using the clamping screw. L, a, depth d, and width b, of the quadrant end face are measured. 2- With the Perspex tank on the bench, the rest period arm is balanced on the knife edges (pivot). The balance pan is hung from the end of the balance arm. 3- A length of hose is connected from the drain mess up to the sump and a length from the bench feed to the triangular aperture on the covering fire of Perspex tank 4- The tank is then levelled using the adjustable feet and spirit level.The issue balance saddle is moved until the balance arm is horizontal. 5- The drain cock is closed and water is admitted until the level reaches the bottom edge of the quadrant. A weight is placed on the balance pan, and water is slowly added into the tank until the balance arm is horizontal. The water level on the quadrant and the weight on the balance pan is recorded. 6- Fine adjustment of the water level ca n be achieved by overfilling and then slowly draining using the occlude cock. 7- The above are repeated for each increment of weight until the water level reached the top of the quadrant end face.Then each increment of weight is removed, noting the weights and water levels until the weights have been removed. RESULTS AND DISCUSSION a= 0. 099m b= 0. 075 m d= 0. 100m l= 0. 274 m ?= 1000 kg/m Weight of load, m(kg ms-2) selection tank height of water(m) Draining tank height of water (m) comely height of water,y (m) Wetted surface area, yb (m ) Hydrostatic pressure, m/yb (Pa) 0. 3924 0. 040 0. 041 0. 041 0. 003075 127. 6098 0. 5886 0. 050 0. 050 0. 050 0. 003750 156. 9600 0. 7848 0. 058 0. 058 0. 058 0. 004350 180. 4138 0. 9810 0. 065 0. 065 0. 065 0. 004875 201. 308 1. 1772 0. 072 0. 073 0. 073 0. 005475 215. 0137 1. 3734 0. 078 0. 077 0. 078 0. 005850 234. 7692 1. 5696 0. 084 0. 083 0. 084 0. 006300 249. 1429 1. 7658 0. 089 0. 088 0. 088 0. 006600 267. 5455 1. 9620 0. 094 0. 094 0. 094 0. 007050 278. 2979 chart of my2 against y Where the slope is -? b2L and the intercept should be ? b2L(a+d) Therefore ?b2L = -93. 9097 ?b2L(a+d) = 101. 7810 CONCLUSION reference book 1- www. wikipedia. org on hydrostatic pressure 2- www. scribd. com on hydrostatic pressure lab report 3- Experiment manual 4- Lab demonstrators chronicle